Jeopardy! ‘Greatest of All Time’ match will crown show's biggest victor
- Author: Michelle Webb Jan 09, 2020,
Jan 09, 2020, 0:34
The legendary player known for his record-setting 74-game streak in 2004 pulled off yet another victory - by just $200 - in the first night of the "Jeopardy!".
Trebek, who will host The Greatest of All Time, recently said that he has rehearsed his final goodbye on the show.
Jeopardy! host Alex Trebek gave a health update and revealed how he plans to end his 35 year run.
Ken Jennings got a chance in the first game to double his winnings with the Daily Double, and though he hesitated at first, he chose to put all his winnings on the line to try and take a sizable lead.
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The "Greatest of All Time" format differs from a regular game.
Episodes are scheduled for Tuesday, Wednesday and Thursday nights at 8 p.m. on ABC.
On each night, the three players will compete in two back-to-back traditional half-hour games whose dollar totals are added together. It was a match format, consisting of two games and the ultimate victor of the match was decided based on total earnings from those two games. With that said, I'm going to predict Brad winning in six matches, with James taking two matches, and Ken capturing one match. Over several appearances in Jeopardy! tournament settings, Rutter has won $4,888,436, making him the highest earning American game show contestant of all time.
ESPN coverage producer James Quintong is a one-time JEOPARDY! champion - watch the video highlights above (from his December 8, 2005 episode) and below (from his December 7, 2005 game-winning episode) - and provides Front Row with this preview.